What is the derivative of a+bcos(x+csin(x)) ?

The derivative of a+bcos(x+csin(x)) is -bsin(x)+csin

What is the first derivative of a+bcos(x+csin(x)) ?

The first derivative of a+bcos(x+csin(x)) is -bsin(x)+csin

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\frac{d}{d x} (a + b cos (x) + cs in (x))

- b sin (x) + cs in

Solution steps

\frac{d}{d x} (a + b cos (x) + cs in (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d a}{d x} + \frac{d}{d x} (b cos (x)) + \frac{d}{d x} (cs in x)

\frac{d a}{d x} = 0

\frac{d}{d x} (b cos (x)) = - b sin (x)

\frac{d}{d x} (cs in x) = cs in

= 0 - b sin (x) + cs in

Simplify

= - b sin (x) + cs in

What is the derivative of a+bcos(x+csin(x)) ?
The derivative of a+bcos(x+csin(x)) is -bsin(x)+csin
What is the first derivative of a+bcos(x+csin(x)) ?
The first derivative of a+bcos(x+csin(x)) is -bsin(x)+csin