What is the tangent of f(x)=9x^2,\at x=-2 ?

The tangent of f(x)=9x^2,\at x=-2 is y=-36x-36

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tangent of f(x)=9x^2,\at x=-2

tangent of

f (x) = 9 x^{2}, at x = - 2

y = - 36 x - 36

Solution steps

Find the tangent point:

(- 2, 36)

Find the slope of

f (x) = 9 x^{2} : \frac{df ( x )}{d x} = 18 x

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 36

Find the line with slope m=

- 36

and passing through

(- 2, 36) : y = - 36 x - 36

y = - 36 x - 36

What is the tangent of f(x)=9x^2,\at x=-2 ?
The tangent of f(x)=9x^2,\at x=-2 is y=-36x-36