What is the integral of tan^2(t) ?

The integral of tan^2(t) is -t+tan(t)+C

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integral of tan^2(t)

\int tan^{2} (t) d t

- t + tan (t) + C

Solution steps

\int tan^{2} (t) d t

Rewrite using trig identities

= \int - 1 + sec^{2} (t) d t

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int 1 d t + \int sec^{2} (t) d t

\int 1 d t = t

\int sec^{2} (t) d t = tan (t)

= - t + tan (t)

Add a constant to the solution

= - t + tan (t) + C