What is area f(x)=x^2+x-56,g(x)=-x^2+3x+4 ?

The answer to area f(x)=x^2+x-56,g(x)=-x^2+3x+4 is 1331/3

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area f(x)=x^2+x-56,g(x)=-x^2+3x+4

area

f (x) = x^{2} + x - 56, g (x) = - x^{2} + 3 x + 4

\frac{1331}{3}

Decimal

443.66666 \dots

Solution steps

Apply the area formula:

\int_{- 5}^{6} x^{2} + x - 56 - (- x^{2} + 3 x + 4) d x

Solve

\int_{- 5}^{6} x^{2} + x - 56 - (- x^{2} + 3 x + 4) d x : \frac{1331}{3}

The area is:

= \frac{1331}{3}

What is area f(x)=x^2+x-56,g(x)=-x^2+3x+4 ?
The answer to area f(x)=x^2+x-56,g(x)=-x^2+3x+4 is 1331/3