What is the tangent of y=sqrt(x+3),(1,2) ?

The tangent of y=sqrt(x+3),(1,2) is y= 1/4 x+7/4

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tangent of y=sqrt(x+3),(1,2)

tangent of

y = x + 3, (1, 2)

y = \frac{1}{4} x + \frac{7}{4}

Solution steps

Find the slope of

y = x + 3 : \frac{d y}{d x} = \frac{1}{2 x + 3}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = \frac{1}{4}

Find the line with slope m=

\frac{1}{4}

and passing through

(1, 2) : y = \frac{1}{4} x + \frac{7}{4}

y = \frac{1}{4} x + \frac{7}{4}

What is the tangent of y=sqrt(x+3),(1,2) ?
The tangent of y=sqrt(x+3),(1,2) is y= 1/4 x+7/4