What is the tangent of f(x)=ax^2,\at x=-2 ?

The tangent of f(x)=ax^2,\at x=-2 is y=-4ax-4a

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

tangent of f(x)=ax^2,\at x=-2

tangent of

f (x) = a x^{2}, at x = - 2

y = - 4 a x - 4 a

Solution steps

Find the tangent point:

(- 2, 4 a)

Find the slope of

f (x) = a x^{2} : \frac{df ( x )}{d x} = 2 a x

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 4 a

Find the line with slope m=

- 4 a

and passing through

(- 2, 4 a) : y = - 4 a x - 4 a

y = - 4 a x - 4 a

What is the tangent of f(x)=ax^2,\at x=-2 ?
The tangent of f(x)=ax^2,\at x=-2 is y=-4ax-4a