What is the integral of 2ycos(y^2) ?

The integral of 2ycos(y^2) is sin(y^2)+C

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integral of 2ycos(y^2)

\int 2 y cos (y^{2}) d y

sin (y^{2}) + C

Solution steps

\int 2 y cos (y^{2}) d y

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int y cos (y^{2}) d y

Apply u-substitution

= 2 \cdot \int \frac{cos ( u )}{2} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \frac{1}{2} \cdot \int cos (u) d u

Use the common integral:

\int cos (u) d u = sin (u)

= 2 \cdot \frac{1}{2} sin (u)

Substitute back

u = y^{2}

= 2 \cdot \frac{1}{2} sin (y^{2})

Simplify

2 \cdot \frac{1}{2} sin (y^{2}) : sin (y^{2})

= sin (y^{2})

Add a constant to the solution

= sin (y^{2}) + C