(\partial)/(\partial x)(tan(8+2x^2y^3z^2))

Lösung

\frac{\partial}{\partial x} (tan (8 + 2 x^{2} y^{3} z^{2}))

sec^{2} (8 + 2 x^{2} y^{3} z^{2}) \cdot 4 y^{3} z^{2} x

Schritte zur Lösung

\frac{\partial}{\partial x} (tan (8 + 2 x^{2} y^{3} z^{2}))

Behandle

y, z

als Konstanten

Wende die Kettenregel an:

sec^{2} (8 + 2 x^{2} y^{3} z^{2}) \frac{\partial}{\partial x} (8 + 2 x^{2} y^{3} z^{2})

= sec^{2} (8 + 2 x^{2} y^{3} z^{2}) \frac{\partial}{\partial x} (8 + 2 x^{2} y^{3} z^{2})

\frac{\partial}{\partial x} (8 + 2 x^{2} y^{3} z^{2}) = 4 y^{3} z^{2} x

= sec^{2} (8 + 2 x^{2} y^{3} z^{2}) \cdot 4 y^{3} z^{2} x

\frac{d}{d x} (x (2 x - 5)^{3})

\int 2 cos (x) sin (x) + \frac{1}{2 x} d x

\int 17 sin^{2} (x) cos^{2} (x) d x

y^{^{'}} - \frac{7}{x} y = \frac{y ^{3}}{x ^{10}}

a re a 75 - 3 x^{2}, [0, 7]