(2xy^2-3y^3)dx+(7-3xy^2)dy=0

Lösung

(2 x y^{2} - 3 y^{3}) d x + (7 - 3 x y^{2}) d y = 0

y = - \frac{- x ^{2} + c _{1} + ( x ^{2} - c _{1} ) ^{2} - 84 x}{6 x}, y = - \frac{- x ^{2} + c _{1} - ( x ^{2} - c _{1} ) ^{2} - 84 x}{6 x}

Schritte zur Lösung

(2 x y^{2} - 3 y^{3}) d x + (7 - 3 x y^{2}) d y = 0

Solve exact ODE:

y = - \frac{- x ^{2} + c _{1} + ( x ^{2} - c _{1} ) ^{2} - 84 x}{6 x}, y = - \frac{- x ^{2} + c _{1} - ( x ^{2} - c _{1} ) ^{2} - 84 x}{6 x}

y = - \frac{- x ^{2} + c _{1} + ( x ^{2} - c _{1} ) ^{2} - 84 x}{6 x}, y = - \frac{- x ^{2} + c _{1} - ( x ^{2} - c _{1} ) ^{2} - 84 x}{6 x}

f (x) = x \cdot e^{\frac{1}{x}}

\frac{d}{d x} (\frac{9}{2 x ^{2}})

y^{^{'}} = \frac{( t ^{2} + t y + y ^{2} )}{t ^{2}}

h \to 0 lim (48 + 12 h + h^{2})

n = 1 \sum \infty \frac{6}{( - 5 ) ^{n}}