What is the solution for (dy}{dx}=\frac{(x^3-2y))/x ?

The solution for (dy}{dx}=\frac{(x^3-2y))/x is y=(x^3)/5+(c_{1})/(x^2)

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(dy}{dx}=\frac{(x^3-2y))/x

\frac{d y}{d x} = \frac{( x ^{3} - 2 y )}{x}

y = \frac{x ^{3}}{5} + \frac{c _{1}}{x ^{2}}

Solution steps

\frac{d y}{d x} = \frac{( x ^{3} - 2 y )}{x}

Solve linear ODE:

y = \frac{x ^{3}}{5} + \frac{c _{1}}{x ^{2}}

y = \frac{x ^{3}}{5} + \frac{c _{1}}{x ^{2}}

What is the solution for (dy}{dx}=\frac{(x^3-2y))/x ?
The solution for (dy}{dx}=\frac{(x^3-2y))/x is y=(x^3)/5+(c_{1})/(x^2)