What is the d/(dθ)(6sin(θ)-8cos(θ)) ?

The d/(dθ)(6sin(θ)-8cos(θ)) is 6cos(θ)+8sin(θ)

What is the first d/(dθ)(6sin(θ)-8cos(θ)) ?

The first d/(dθ)(6sin(θ)-8cos(θ)) is 6cos(θ)+8sin(θ)

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\frac{d}{d θ} (6 sin (θ) - 8 cos (θ))

6 cos (θ) + 8 sin (θ)

Solution steps

\frac{d}{d θ} (6 sin (θ) - 8 cos (θ))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d θ} (6 sin (θ)) - \frac{d}{d θ} (8 cos (θ))

\frac{d}{d θ} (6 sin (θ)) = 6 cos (θ)

\frac{d}{d θ} (8 cos (θ)) = - 8 sin (θ)

= 6 cos (θ) - (- 8 sin (θ))

Simplify

= 6 cos (θ) + 8 sin (θ)

What is the d/(dθ)(6sin(θ)-8cos(θ)) ?
The d/(dθ)(6sin(θ)-8cos(θ)) is 6cos(θ)+8sin(θ)
What is the first d/(dθ)(6sin(θ)-8cos(θ)) ?
The first d/(dθ)(6sin(θ)-8cos(θ)) is 6cos(θ)+8sin(θ)