What is the tangent of f(x)=2x^2-4x,\at x=-1 ?

The tangent of f(x)=2x^2-4x,\at x=-1 is y=-8x-2

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tangent of f(x)=2x^2-4x,\at x=-1

tangent of

f (x) = 2 x^{2} - 4 x, at x = - 1

y = - 8 x - 2

Solution steps

Find the tangent point:

(- 1, 6)

Find the slope of

f (x) = 2 x^{2} - 4 x : \frac{df ( x )}{d x} = 4 x - 4

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 8

Find the line with slope m=

- 8

and passing through

(- 1, 6) : y = - 8 x - 2

y = - 8 x - 2

What is the tangent of f(x)=2x^2-4x,\at x=-1 ?
The tangent of f(x)=2x^2-4x,\at x=-1 is y=-8x-2