What is (\partial}{\partial v}(\frac{u+v)/2) ?

The answer to (\partial}{\partial v}(\frac{u+v)/2) is 1/2

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(\partial}{\partial v}(\frac{u+v)/2)

\frac{\partial}{\partial v} (\frac{u + v}{2})

\frac{1}{2}

Decimal

0.5

Solution steps

\frac{\partial}{\partial v} (\frac{u + v}{2})

Treat

u

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{2} \frac{\partial}{\partial v} (u + v)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{1}{2} (\frac{\partial}{\partial v} (u) + \frac{\partial}{\partial v} (v))

\frac{\partial}{\partial v} (u) = 0

\frac{\partial}{\partial v} (v) = 1

= \frac{1}{2} (0 + 1)

Simplify

= \frac{1}{2}

What is (\partial}{\partial v}(\frac{u+v)/2) ?
The answer to (\partial}{\partial v}(\frac{u+v)/2) is 1/2