What is the derivative of g(x)=2x^{0.8}+4x^{-0.8} ?

The derivative of g(x)=2x^{0.8}+4x^{-0.8} is (1.6)/(x^{0.2)}-(3.2)/(x^{1.8)}

What is the first derivative of g(x)=2x^{0.8}+4x^{-0.8} ?

The first derivative of g(x)=2x^{0.8}+4x^{-0.8} is (1.6)/(x^{0.2)}-(3.2)/(x^{1.8)}

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derivative of

g (x) = 2 x^{0.8} + 4 x^{- 0.8}

\frac{1.6}{x ^{0.2}} - \frac{3.2}{x ^{1.8}}

Solution steps

\frac{d}{d x} (2 x^{0.8} + 4 x^{- 0.8})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{0.8}) + \frac{d}{d x} (4 x^{- 0.8})

\frac{d}{d x} (2 x^{0.8}) = \frac{1.6}{x ^{0.2}}

\frac{d}{d x} (4 x^{- 0.8}) = - \frac{3.2}{x ^{1.8}}

= \frac{1.6}{x ^{0.2}} - \frac{3.2}{x ^{1.8}}

What is the derivative of g(x)=2x^{0.8}+4x^{-0.8} ?
The derivative of g(x)=2x^{0.8}+4x^{-0.8} is (1.6)/(x^{0.2)}-(3.2)/(x^{1.8)}
What is the first derivative of g(x)=2x^{0.8}+4x^{-0.8} ?
The first derivative of g(x)=2x^{0.8}+4x^{-0.8} is (1.6)/(x^{0.2)}-(3.2)/(x^{1.8)}