What is the tangent of f(x)=2x^2-5x+1,\at x=2 ?

The tangent of f(x)=2x^2-5x+1,\at x=2 is y=3x-7

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tangent of f(x)=2x^2-5x+1,\at x=2

tangent of

f (x) = 2 x^{2} - 5 x + 1, at x = 2

y = 3 x - 7

Solution steps

Find the tangent point:

(2, - 1)

Find the slope of

f (x) = 2 x^{2} - 5 x + 1 : \frac{df ( x )}{d x} = 4 x - 5

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 3

Find the line with slope m=

3

and passing through

(2, - 1) : y = 3 x - 7

y = 3 x - 7

What is the tangent of f(x)=2x^2-5x+1,\at x=2 ?
The tangent of f(x)=2x^2-5x+1,\at x=2 is y=3x-7