(\partial)/(\partial x)(ln(x+y)+x*cos(y))

解答

\frac{\partial}{\partial x} (ln (x + y) + x \cdot cos (y))

\frac{1}{x + y} + cos (y)

求解步骤

\frac{\partial}{\partial x} (ln (x + y) + x cos (y))

将

y

视为常数

使用微分加减法定则:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (ln (x + y)) + \frac{\partial}{\partial x} (x cos (y))

\frac{\partial}{\partial x} (ln (x + y)) = \frac{1}{x + y}

\frac{\partial}{\partial x} (x cos (y)) = cos (y)

= \frac{1}{x + y} + cos (y)

\int 4 x^{3} - 3 x + x^{e} d x

\frac{d}{d x} (ln (x e^{- 9 x}))

\frac{\partial}{\partial x} (\frac{c - b}{a - x})

y^{^{'}} = \frac{( 1 + x )}{x y ^{14}}

t an g e n t y = (x^{2} - 15)^{4}, at x = 4