What is the derivative of 12x^5-8x^4+20x^3 ?

The derivative of 12x^5-8x^4+20x^3 is 60x^4-32x^3+60x^2

What is the first derivative of 12x^5-8x^4+20x^3 ?

The first derivative of 12x^5-8x^4+20x^3 is 60x^4-32x^3+60x^2

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derivative of

12 x^{5} - 8 x^{4} + 20 x^{3}

60 x^{4} - 32 x^{3} + 60 x^{2}

Solution steps

\frac{d}{d x} (12 x^{5} - 8 x^{4} + 20 x^{3})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (12 x^{5}) - \frac{d}{d x} (8 x^{4}) + \frac{d}{d x} (20 x^{3})

\frac{d}{d x} (12 x^{5}) = 60 x^{4}

\frac{d}{d x} (8 x^{4}) = 32 x^{3}

\frac{d}{d x} (20 x^{3}) = 60 x^{2}

= 60 x^{4} - 32 x^{3} + 60 x^{2}

What is the derivative of 12x^5-8x^4+20x^3 ?
The derivative of 12x^5-8x^4+20x^3 is 60x^4-32x^3+60x^2
What is the first derivative of 12x^5-8x^4+20x^3 ?
The first derivative of 12x^5-8x^4+20x^3 is 60x^4-32x^3+60x^2