What is the tangent of f(x)= 1/(x-1),(-7,-1/8) ?

The tangent of f(x)= 1/(x-1),(-7,-1/8) is y=-1/64 x-15/64

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tangent of f(x)= 1/(x-1),(-7,-1/8)

tangent of

f (x) = \frac{1}{x - 1}, (- 7, - \frac{1}{8})

y = - \frac{1}{64} x - \frac{15}{64}

Solution steps

Find the slope of

f (x) = \frac{1}{x - 1} : \frac{df ( x )}{d x} = - \frac{1}{( x - 1 ) ^{2}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - \frac{1}{64}

Find the line with slope m=

- \frac{1}{64}

and passing through

(- 7, - \frac{1}{8}) : y = - \frac{1}{64} x - \frac{15}{64}

y = - \frac{1}{64} x - \frac{15}{64}

What is the tangent of f(x)= 1/(x-1),(-7,-1/8) ?
The tangent of f(x)= 1/(x-1),(-7,-1/8) is y=-1/64 x-15/64