What is the tangent of f(x)=2x^{-1},\at x=5 ?

The tangent of f(x)=2x^{-1},\at x=5 is y=-2/25 x+4/5

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tangent of f(x)=2x^{-1},\at x=5

tangent of

f (x) = 2 x^{- 1}, at x = 5

y = - \frac{2}{25} x + \frac{4}{5}

Solution steps

Find the tangent point:

(5, \frac{2}{5})

Find the slope of

f (x) = 2 x^{- 1} : \frac{df ( x )}{d x} = - \frac{2}{x ^{2}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - \frac{2}{25}

Find the line with slope m=

- \frac{2}{25}

and passing through

(5, \frac{2}{5}) : y = - \frac{2}{25} x + \frac{4}{5}

y = - \frac{2}{25} x + \frac{4}{5}

What is the tangent of f(x)=2x^{-1},\at x=5 ?
The tangent of f(x)=2x^{-1},\at x=5 is y=-2/25 x+4/5