What is the integral of cos^4(3y)sin(3y) ?

The integral of cos^4(3y)sin(3y) is -1/15 cos^5(3y)+C

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integral of cos^4(3y)sin(3y)

\int cos^{4} (3 y) sin (3 y) d y

- \frac{1}{15} cos^{5} (3 y) + C

Solution steps

\int cos^{4} (3 y) sin (3 y) d y

Apply u-substitution

= \int cos^{4} (u) sin (u) \frac{1}{3} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{3} \cdot \int cos^{4} (u) sin (u) d u

Apply u-substitution

= \frac{1}{3} \cdot \int - v^{4} d v

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{3} (- \int v^{4} d v)

Apply the Power Rule

= \frac{1}{3} (- \frac{v ^{5}}{5})

Substitute back

= \frac{1}{3} (- \frac{cos ^{5} ( 3 y )}{5})

Simplify

\frac{1}{3} (- \frac{cos ^{5} ( 3 y )}{5}) : - \frac{1}{15} cos^{5} (3 y)

= - \frac{1}{15} cos^{5} (3 y)

Add a constant to the solution

= - \frac{1}{15} cos^{5} (3 y) + C

What is the integral of cos^4(3y)sin(3y) ?
The integral of cos^4(3y)sin(3y) is -1/15 cos^5(3y)+C