Solution
Solution
Solution steps
Treat as constants
Apply the chain rule:
Simplify
Popular Examples
tangent of f(x)= 1/(1+5x^2),\at x=-1d/(dt)(7t)(\partial)/(\partial x)(x/y-sin(y))xy^{''}+2y^'=12x^2integral from-1 to 1 of (4x)/((x+3)^2)
Frequently Asked Questions (FAQ)
What is (\partial)/(\partial x)(ln(3x+6y+9t)) ?
The answer to (\partial)/(\partial x)(ln(3x+6y+9t)) is 1/(x+2y+3t)