What is (\partial)/(\partial y)(e^{xy}-z) ?

The answer to (\partial)/(\partial y)(e^{xy}-z) is e^{xy}x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

(\partial)/(\partial y)(e^{xy}-z)

\frac{\partial}{\partial y} (e^{x y} - z)

e^{x y} x

Solution steps

\frac{\partial}{\partial y} (e^{x y} - z)

Treat

x, z

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (e^{x y}) - \frac{\partial}{\partial y} (z)

\frac{\partial}{\partial y} (e^{x y}) = e^{x y} x

\frac{\partial}{\partial y} (z) = 0

= e^{x y} x - 0

Simplify

= e^{x y} x

What is (\partial)/(\partial y)(e^{xy}-z) ?
The answer to (\partial)/(\partial y)(e^{xy}-z) is e^{xy}x