derivative of x^4+3x^3-x^2

Lösung

\frac{d}{d x} (x^{4} + 3 x^{3} - x^{2})

4 x^{3} + 9 x^{2} - 2 x

Schritte zur Lösung

\frac{d}{d x} (x^{4} + 3 x^{3} - x^{2})

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{4}) + \frac{d}{d x} (3 x^{3}) - \frac{d}{d x} (x^{2})

\frac{d}{d x} (x^{4}) = 4 x^{3}

\frac{d}{d x} (3 x^{3}) = 9 x^{2}

\frac{d}{d x} (x^{2}) = 2 x

= 4 x^{3} + 9 x^{2} - 2 x

in v erse l a pl a ce \frac{s + 1}{( s ^{2} - 4 s ) ( s + 5 )}

x \to 2 lim (ln (x^{2} - 4))

\frac{d}{d x} (\frac{e ^{x}}{x \cdot cos ( x )})

f^{^{''}} + 16 f = sin (2 x)

\int_{6}^{12} 144 - x^{2} d x