What is the solution for (dy)/(dt)=(8ty)/(t^2+1),y(0)=-2 ?

The solution for (dy)/(dt)=(8ty)/(t^2+1),y(0)=-2 is y=-2(t^8+4t^6+6t^4+4t^2+1)

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(dy)/(dt)=(8ty)/(t^2+1),y(0)=-2

\frac{d y}{d t} = \frac{8 t y}{t ^{2} + 1}, y (0) = - 2

y = - 2 (t^{8} + 4 t^{6} + 6 t^{4} + 4 t^{2} + 1)

Solution steps

\frac{d y}{d t} = \frac{8 t y}{t ^{2} + 1}

Solve linear ODE:

y = - 2 (t^{8} + 4 t^{6} + 6 t^{4} + 4 t^{2} + 1)

y = - 2 (t^{8} + 4 t^{6} + 6 t^{4} + 4 t^{2} + 1)

What is the solution for (dy)/(dt)=(8ty)/(t^2+1),y(0)=-2 ?
The solution for (dy)/(dt)=(8ty)/(t^2+1),y(0)=-2 is y=-2(t^8+4t^6+6t^4+4t^2+1)