What is the tangent of e^x(7-5x+3x^2),\at x=0 ?

The tangent of e^x(7-5x+3x^2),\at x=0 is y=2x+7

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tangent of e^x(7-5x+3x^2),\at x=0

tangent of

e^{x} (7 - 5 x + 3 x^{2}), at x = 0

y = 2 x + 7

Solution steps

Find the tangent point:

(0, 7)

Find the slope of

y = e^{x} (7 - 5 x + 3 x^{2}) : \frac{d y}{d x} = 3 e^{x} x^{2} + e^{x} x + 2 e^{x}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 2

Find the line with slope m=

2

and passing through

(0, 7) : y = 2 x + 7

y = 2 x + 7

What is the tangent of e^x(7-5x+3x^2),\at x=0 ?
The tangent of e^x(7-5x+3x^2),\at x=0 is y=2x+7