What is the tangent of-3(x)^5+9(x)^3,\at x=-1 ?

The tangent of-3(x)^5+9(x)^3,\at x=-1 is y=12x+6

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tangent of-3(x)^5+9(x)^3,\at x=-1

tangent of

- 3 (x)^{5} + 9 (x)^{3}, at x = - 1

y = 12 x + 6

Solution steps

Find the tangent point:

(- 1, - 6)

Find the slope of

y = - 3 x^{5} + 9 x^{3} : \frac{d y}{d x} = - 15 x^{4} + 27 x^{2}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 12

Find the line with slope m=

12

and passing through

(- 1, - 6) : y = 12 x + 6

y = 12 x + 6

What is the tangent of-3(x)^5+9(x)^3,\at x=-1 ?
The tangent of-3(x)^5+9(x)^3,\at x=-1 is y=12x+6