What is inverse oflaplace 89/2 s ?

The answer to inverse oflaplace 89/2 s is 89/2 \delta'(t)

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inverse oflaplace 89/2 s

inverse laplace

\frac{89}{2} s

\frac{89}{2} δ' (t)

Solution steps

L^{- 1} {\frac{89}{2} s}

Use the constant multiplication property of Inverse Laplace Transform:

For function

f (t)

and constant

a : L^{- 1} {a \cdot f (t)} = a \cdot L^{- 1} {f (t)}

= \frac{89}{2} L^{- 1} {s}

L^{- 1} {s} : δ^{'} (t)

= \frac{89}{2} δ^{^{'}} (t)

What is inverse oflaplace 89/2 s ?
The answer to inverse oflaplace 89/2 s is 89/2 \delta'(t)