What is the derivative of (x+1/x) ?

The derivative of (x+1/x) is -1/(x^2)

What is the first derivative of (x+1/x) ?

The first derivative of (x+1/x) is -1/(x^2)

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\frac{d}{d x} (\frac{x + 1}{x})

- \frac{1}{x ^{2}}

Solution steps

\frac{d}{d x} (\frac{x + 1}{x})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( x + 1 ) x - \frac{d x}{d x} ( x + 1 )}{x ^{2}}

\frac{d}{d x} (x + 1) = 1

\frac{d x}{d x} = 1

= \frac{1 \cdot x - 1 \cdot ( x + 1 )}{x ^{2}}

Simplify

\frac{1 \cdot x - 1 \cdot ( x + 1 )}{x ^{2}} : - \frac{1}{x ^{2}}

= - \frac{1}{x ^{2}}

What is the derivative of (x+1/x) ?
The derivative of (x+1/x) is -1/(x^2)
What is the first derivative of (x+1/x) ?
The first derivative of (x+1/x) is -1/(x^2)