What is the solution for y^'= y/2+4e^{t/2} ?

The solution for y^'= y/2+4e^{t/2} is y=4e^{t/2}t+c_{1}e^{t/2}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

y^'= y/2+4e^{t/2}

y^{^{'}} = \frac{y}{2} + 4 e^{\frac{t}{2}}

y = 4 e^{\frac{t}{2}} t + c_{1} e^{\frac{t}{2}}

Solution steps

y^{'} (t) = \frac{y}{2} + 4 e^{\frac{t}{2}}

Solve linear ODE:

y = 4 e^{\frac{t}{2}} t + c_{1} e^{\frac{t}{2}}

y = 4 e^{\frac{t}{2}} t + c_{1} e^{\frac{t}{2}}

What is the solution for y^'= y/2+4e^{t/2} ?
The solution for y^'= y/2+4e^{t/2} is y=4e^{t/2}t+c_{1}e^{t/2}