What is the derivative of f(x)=-8x^3+24x+9 ?

The derivative of f(x)=-8x^3+24x+9 is -24x^2+24

What is the first derivative of f(x)=-8x^3+24x+9 ?

The first derivative of f(x)=-8x^3+24x+9 is -24x^2+24

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derivative of

f (x) = - 8 x^{3} + 24 x + 9

- 24 x^{2} + 24

Solution steps

\frac{d}{d x} (- 8 x^{3} + 24 x + 9)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (8 x^{3}) + \frac{d}{d x} (24 x) + \frac{d}{d x} (9)

\frac{d}{d x} (8 x^{3}) = 24 x^{2}

\frac{d}{d x} (24 x) = 24

\frac{d}{d x} (9) = 0

= - 24 x^{2} + 24 + 0

Simplify

= - 24 x^{2} + 24

What is the derivative of f(x)=-8x^3+24x+9 ?
The derivative of f(x)=-8x^3+24x+9 is -24x^2+24
What is the first derivative of f(x)=-8x^3+24x+9 ?
The first derivative of f(x)=-8x^3+24x+9 is -24x^2+24