What is the solution for (y+sqrt(x^2-y^2))dx-xdy=0 ?

The solution for (y+sqrt(x^2-y^2))dx-xdy=0 is y=sin(ln(x)+c_{1})x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

(y+sqrt(x^2-y^2))dx-xdy=0

(y + x^{2} - y^{2}) d x - x d y = 0

y = sin (ln (x) + c_{1}) x

Solution steps

(y + x^{2} - y^{2}) d x - x d y = 0

Solve using substitution:

y = sin (ln (x) + c_{1}) x

y = sin (ln (x) + c_{1}) x

What is the solution for (y+sqrt(x^2-y^2))dx-xdy=0 ?
The solution for (y+sqrt(x^2-y^2))dx-xdy=0 is y=sin(ln(x)+c_{1})x