What is the tangent of y=2x^2+3x,(-2,2) ?

The tangent of y=2x^2+3x,(-2,2) is y=-5x-8

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tangent of y=2x^2+3x,(-2,2)

tangent of

y = 2 x^{2} + 3 x, (- 2, 2)

y = - 5 x - 8

Solution steps

Find the slope of

y = 2 x^{2} + 3 x : \frac{d y}{d x} = 4 x + 3

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 5

Find the line with slope m=

- 5

and passing through

(- 2, 2) : y = - 5 x - 8

y = - 5 x - 8

What is the tangent of y=2x^2+3x,(-2,2) ?
The tangent of y=2x^2+3x,(-2,2) is y=-5x-8