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Popular Calculus >

integral of 2y-1

Solution

\int 2 y - 1 d y

Solution

y^{2} - y + C

Solution steps

\int 2 y - 1 d y

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 2 y d y - \int 1 d y

\int 2 y d y = y^{2}

\int 1 d y = y

= y^{2} - y

Add a constant to the solution

= y^{2} - y + C

Graph

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Frequently Asked Questions (FAQ)

What is the integral of 2y-1 ?
The integral of 2y-1 is y^2-y+C