What is the integral of 2/7 x^2+1 ?

The integral of 2/7 x^2+1 is (2x^3)/(21)+x+C

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integral of 2/7 x^2+1

\int \frac{2}{7} x^{2} + 1 d x

\frac{2 x ^{3}}{21} + x + C

Solution steps

\int \frac{2}{7} x^{2} + 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{2}{7} x^{2} d x + \int 1 d x

\int \frac{2}{7} x^{2} d x = \frac{2 x ^{3}}{21}

\int 1 d x = x

= \frac{2 x ^{3}}{21} + x

Add a constant to the solution

= \frac{2 x ^{3}}{21} + x + C

What is the integral of 2/7 x^2+1 ?
The integral of 2/7 x^2+1 is (2x^3)/(21)+x+C