4y^{''}+3y^'+7y=0

Lösung

4 y^{^{''}} + 3 y^{^{'}} + 7 y = 0

y = e^{- \frac{3 t}{8}} (c_{1} cos (\frac{103 t}{8}) + c_{2} sin (\frac{103 t}{8}))

Schritte zur Lösung

4 y^{''} (t) + 3 y^{'} (t) + 7 y = 0

Solve linear ODE:

y = e^{- \frac{3 t}{8}} (c_{1} cos (\frac{103 t}{8}) + c_{2} sin (\frac{103 t}{8}))

y = e^{- \frac{3 t}{8}} (c_{1} cos (\frac{103 t}{8}) + c_{2} sin (\frac{103 t}{8}))