integral of (6+t+t^2)/(sqrt(t))

Lösung

\int \frac{6 + t + t ^{2}}{t} d t

12 t + \frac{2}{3} t^{\frac{3}{2}} + \frac{2}{5} t^{\frac{5}{2}} + C

Schritte zur Lösung

\int \frac{6 + t + t ^{2}}{t} d t

Multipliziere aus

\frac{6 + t + t ^{2}}{t} : \frac{6}{t} + t + t^{\frac{3}{2}}

= \int \frac{6}{t} + t + t^{\frac{3}{2}} d t

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{6}{t} d t + \int t d t + \int t^{\frac{3}{2}} d t

\int \frac{6}{t} d t = 12 t

\int t d t = \frac{2}{3} t^{\frac{3}{2}}

\int t^{\frac{3}{2}} d t = \frac{2}{5} t^{\frac{5}{2}}

= 12 t + \frac{2}{3} t^{\frac{3}{2}} + \frac{2}{5} t^{\frac{5}{2}}

Füge eine Konstante zur Lösung hinzu

= 12 t + \frac{2}{3} t^{\frac{3}{2}} + \frac{2}{5} t^{\frac{5}{2}} + C