What is the tangent of f(x)=(2x-5)^3,\at x=1 ?

The tangent of f(x)=(2x-5)^3,\at x=1 is y=54x-81

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tangent of f(x)=(2x-5)^3,\at x=1

tangent of

f (x) = (2 x - 5)^{3}, at x = 1

y = 54 x - 81

Solution steps

Find the tangent point:

(1, - 27)

Find the slope of

f (x) = (2 x - 5)^{3} : \frac{df ( x )}{d x} = 6 (2 x - 5)^{2}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 54

Find the line with slope m=

54

and passing through

(1, - 27) : y = 54 x - 81

y = 54 x - 81

What is the tangent of f(x)=(2x-5)^3,\at x=1 ?
The tangent of f(x)=(2x-5)^3,\at x=1 is y=54x-81