What is the tangent of f(x)=((x+3)/(x-3))^2,\at x=4 ?

The tangent of f(x)=((x+3)/(x-3))^2,\at x=4 is y=-84x+385

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tangent of f(x)=((x+3)/(x-3))^2,\at x=4

tangent of

f (x) = (\frac{x + 3}{x - 3})^{2}, at x = 4

y = - 84 x + 385

Solution steps

Find the tangent point:

(4, 49)

Find the slope of

f (x) = (\frac{x + 3}{x - 3})^{2} : \frac{df ( x )}{d x} = - \frac{12 ( x + 3 )}{( x - 3 ) ^{3}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 84

Find the line with slope m=

- 84

and passing through

(4, 49) : y = - 84 x + 385

y = - 84 x + 385

What is the tangent of f(x)=((x+3)/(x-3))^2,\at x=4 ?
The tangent of f(x)=((x+3)/(x-3))^2,\at x=4 is y=-84x+385