What is (\partial}{\partial x}(\frac{(7x+7y))/z) ?

The answer to (\partial}{\partial x}(\frac{(7x+7y))/z) is 7/z

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

(\partial}{\partial x}(\frac{(7x+7y))/z)

\frac{\partial}{\partial x} (\frac{( 7 x + 7 y )}{z})

\frac{7}{z}

Solution steps

\frac{\partial}{\partial x} (\frac{( 7 x + 7 y )}{z})

Treat

y, z

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{z} \frac{\partial}{\partial x} (7 x + 7 y)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{1}{z} (\frac{\partial}{\partial x} (7 x) + \frac{\partial}{\partial x} (7 y))

\frac{\partial}{\partial x} (7 x) = 7

\frac{\partial}{\partial x} (7 y) = 0

= \frac{1}{z} (7 + 0)

Simplify

\frac{1}{z} (7 + 0) : \frac{7}{z}

= \frac{7}{z}

What is (\partial}{\partial x}(\frac{(7x+7y))/z) ?
The answer to (\partial}{\partial x}(\frac{(7x+7y))/z) is 7/z