What is the limit as x approaches 0 of (1+bx)^{1/x} ?

The limit as x approaches 0 of (1+bx)^{1/x} is e^b

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limit as x approaches 0 of (1+bx)^{1/x}

x \to 0 lim ((1 + b x)^{\frac{1}{x}})

e^{b}

Solution steps

x \to 0 lim ((1 + b x)^{\frac{1}{x}})

Apply exponent rules

= x \to 0 lim (e^{\frac{1}{x} l n (1 + b x)})

Apply the Limit Chain Rule:

e^{b}

= e^{b}

What is the limit as x approaches 0 of (1+bx)^{1/x} ?
The limit as x approaches 0 of (1+bx)^{1/x} is e^b