What is the tangent of f(x)=sqrt(x)(x+1),\at x=1 ?

The tangent of f(x)=sqrt(x)(x+1),\at x=1 is y=2x

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tangent of f(x)=sqrt(x)(x+1),\at x=1

tangent of

f (x) = x (x + 1), at x = 1

y = 2 x

Solution steps

Find the tangent point:

(1, 2)

Find the slope of

f (x) = x (x + 1) : \frac{df ( x )}{d x} = \frac{3 x + 1}{2 x}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 2

Find the line with slope m=

2

and passing through

(1, 2) : y = 2 x

y = 2 x

What is the tangent of f(x)=sqrt(x)(x+1),\at x=1 ?
The tangent of f(x)=sqrt(x)(x+1),\at x=1 is y=2x