What is the integral of 1+sec^2(x) ?

The integral of 1+sec^2(x) is x+tan(x)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral of 1+sec^2(x)

\int 1 + sec^{2} (x) d x

x + tan (x) + C

Solution steps

\int 1 + sec^{2} (x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 1 d x + \int sec^{2} (x) d x

\int 1 d x = x

\int sec^{2} (x) d x = tan (x)

= x + tan (x)

Add a constant to the solution

= x + tan (x) + C