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Popular Calculus >

integral from 1 to 2 of (2x^3-4)

Solution

\int_{1}^{2} (2 x^{3} - 4) d x

Solution

\frac{7}{2}

+1

Decimal

3.5

Solution steps

\int_{1}^{2} 2 x^{3} - 4 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{2} 2 x^{3} d x - \int_{1}^{2} 4 d x

\int_{1}^{2} 2 x^{3} d x = \frac{15}{2}

\int_{1}^{2} 4 d x = 4

= \frac{15}{2} - 4

Simplify

\frac{15}{2} - 4 : \frac{7}{2}

= \frac{7}{2}

Graph

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Frequently Asked Questions (FAQ)

What is the integral from 1 to 2 of (2x^3-4) ?
The integral from 1 to 2 of (2x^3-4) is 7/2