What is area f(x)=x^3-2x^2,g(x)=x^2-2x ?

The answer to area f(x)=x^3-2x^2,g(x)=x^2-2x is 1/2

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area f(x)=x^3-2x^2,g(x)=x^2-2x

area

f (x) = x^{3} - 2 x^{2}, g (x) = x^{2} - 2 x

\frac{1}{2}

Decimal

0.5

Solution steps

Apply the area formula:

\int_{0}^{2} x^{3} - 2 x^{2} - (x^{2} - 2 x) d x

Solve

\int_{0}^{2} x^{3} - 2 x^{2} - (x^{2} - 2 x) d x : \frac{1}{2}

The area is:

= \frac{1}{2}

What is area f(x)=x^3-2x^2,g(x)=x^2-2x ?
The answer to area f(x)=x^3-2x^2,g(x)=x^2-2x is 1/2