What is (\partial)/(\partial x)(x^3y^2-y) ?

The answer to (\partial)/(\partial x)(x^3y^2-y) is 3x^2y^2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

(\partial)/(\partial x)(x^3y^2-y)

\frac{\partial}{\partial x} (x^{3} y^{2} - y)

3 x^{2} y^{2}

Solution steps

\frac{\partial}{\partial x} (x^{3} y^{2} - y)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x^{3} y^{2}) - \frac{\partial}{\partial x} (y)

\frac{\partial}{\partial x} (x^{3} y^{2}) = 3 y^{2} x^{2}

\frac{\partial}{\partial x} (y) = 0

= 3 y^{2} x^{2} - 0

Simplify

= 3 x^{2} y^{2}

What is (\partial)/(\partial x)(x^3y^2-y) ?
The answer to (\partial)/(\partial x)(x^3y^2-y) is 3x^2y^2