What is the tangent of f(x)=x^2-2,(-3,7) ?

The tangent of f(x)=x^2-2,(-3,7) is y=-6x-11

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tangent of f(x)=x^2-2,(-3,7)

tangent of

f (x) = x^{2} - 2, (- 3, 7)

y = - 6 x - 11

Solution steps

Find the slope of

f (x) = x^{2} - 2 : \frac{df ( x )}{d x} = 2 x

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 6

Find the line with slope m=

- 6

and passing through

(- 3, 7) : y = - 6 x - 11

y = - 6 x - 11

What is the tangent of f(x)=x^2-2,(-3,7) ?
The tangent of f(x)=x^2-2,(-3,7) is y=-6x-11