What is the derivative of-x^3+3x^2+9x-1 ?

The derivative of-x^3+3x^2+9x-1 is -3x^2+6x+9

What is the first derivative of-x^3+3x^2+9x-1 ?

The first derivative of-x^3+3x^2+9x-1 is -3x^2+6x+9

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\frac{d}{d x} (- x^{3} + 3 x^{2} + 9 x - 1)

- 3 x^{2} + 6 x + 9

Solution steps

\frac{d}{d x} (- x^{3} + 3 x^{2} + 9 x - 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (x^{3}) + \frac{d}{d x} (3 x^{2}) + \frac{d}{d x} (9 x) - \frac{d}{d x} (1)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (9 x) = 9

\frac{d}{d x} (1) = 0

= - 3 x^{2} + 6 x + 9 - 0

Simplify

= - 3 x^{2} + 6 x + 9

What is the derivative of-x^3+3x^2+9x-1 ?
The derivative of-x^3+3x^2+9x-1 is -3x^2+6x+9
What is the first derivative of-x^3+3x^2+9x-1 ?
The first derivative of-x^3+3x^2+9x-1 is -3x^2+6x+9