What is area x=4y-8,x=sqrt(4y+1) ?

The answer to area x=4y-8,x=sqrt(4y+1) is (37sqrt(37))/(24)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

area x=4y-8,x=sqrt(4y+1)

area

x = 4 y - 8, x = 4 y + 1

\frac{37 37}{24}

Decimal

9.37759 \dots

Solution steps

Isolate

y

for

x = 4 y - 8 : y = \frac{x + 8}{4}

Isolate

y

for

x = 4 y + 1 : y = \frac{x ^{2} - 1}{4} {x \geq 0}

Apply the area formula:

\int_{\frac{1 - 37}{2}}^{\frac{1 + 37}{2}} \frac{x + 8}{4} - \frac{x ^{2} - 1}{4} d x

Solve

\int_{\frac{1 - 37}{2}}^{\frac{1 + 37}{2}} \frac{x + 8}{4} - \frac{x ^{2} - 1}{4} d x : \frac{37 37}{24}

The area is:

= \frac{37 37}{24}

What is area x=4y-8,x=sqrt(4y+1) ?
The answer to area x=4y-8,x=sqrt(4y+1) is (37sqrt(37))/(24)