What is the solution for y^{''}-3y^'+2y=e^{5x} ?

The solution for y^{''}-3y^'+2y=e^{5x} is y=c_{1}e^{2x}+c_{2}e^x+1/12 e^{5x}

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y^{''}-3y^'+2y=e^{5x}

y^{^{''}} - 3 y^{^{'}} + 2 y = e^{5 x}

y = c_{1} e^{2 x} + c_{2} e^{x} + \frac{1}{12} e^{5 x}

Solution steps

y^{''} (x) - 3 y^{'} (x) + 2 y = e^{5 x}

Solve linear ODE:

y = c_{1} e^{2 x} + c_{2} e^{x} + \frac{1}{12} e^{5 x}

y = c_{1} e^{2 x} + c_{2} e^{x} + \frac{1}{12} e^{5 x}

What is the solution for y^{''}-3y^'+2y=e^{5x} ?
The solution for y^{''}-3y^'+2y=e^{5x} is y=c_{1}e^{2x}+c_{2}e^x+1/12 e^{5x}