What is area x^2-4x+7,2x^2-3x+1 ?

The answer to area x^2-4x+7,2x^2-3x+1 is 125/6

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area x^2-4x+7,2x^2-3x+1

area

x^{2} - 4 x + 7, 2 x^{2} - 3 x + 1

\frac{125}{6}

Decimal

20.83333 \dots

Solution steps

Apply the area formula:

\int_{- 3}^{2} x^{2} - 4 x + 7 - (2 x^{2} - 3 x + 1) d x

Solve

\int_{- 3}^{2} x^{2} - 4 x + 7 - (2 x^{2} - 3 x + 1) d x : \frac{125}{6}

The area is:

= \frac{125}{6}

What is area x^2-4x+7,2x^2-3x+1 ?
The answer to area x^2-4x+7,2x^2-3x+1 is 125/6